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Mathematics
Lauryn Dillon
23 February, 12:37
16a^-2b^7c^0/8a^2b^-5
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2
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Alice Duarte
23 February, 15:21
0
(2b^12) / (a^3)
The c is no longer in the equation cause anything to the zero power is one.
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Cayden Coffey
23 February, 15:27
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Simplify the following:
(16 b^7 c^0 a^2) / (8 a^2 b^5)
(16 b^7 c^0 a^2) / (a^2 b^5*8) = a^2/a^2 * (16 b^7 c^0) / (b^5*8) = (16 b^7 c^0) / (b^5*8):
(16 b^7 c^0) / (8 b^5)
16/8 = (8*2) / 8 = 2:
(2 b^7 c^0) / b^5
Combine powers. (2 b^7 c^0) / b^5 = 2 b^ (7 - 5) c^0:
2 b^ (7 - 5) c^0
7 - 5 = 2:
2 b^2 c^0
c^0 = 1:
2*1 b^2
Write 2 b^2*1 as 2 b^2:
Answer: 2 b^2
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