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Mathematics
Jesse Nicholson
24 June, 23:48
Find a6 of the geometric sequence: a1=4 and a3=36
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Paxton Butler
25 June, 01:43
0
Geometric sequence
an=a1 (r) ^ (n-1)
so
given
a1=4
and a3=36
36=a3=4 (r) ^ (3-1)
36=4 (r) ^2
9=r^2
3=r
an=4 (3) ^ (n-1)
a6 is
a6=4 (3) ^ (6-1)
a6=4 (3) ^5
a6=4 (243)
a6=972
a6=972
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