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30 October, 06:57

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x^2 - 6x + 1 = 0

three real-number roots

two real-number roots

one real-number root

no real-number roots

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Answers (1)
  1. 30 October, 09:39
    0
    In a quadratic equation with the general formula of:

    ax^2 + bx + c = 0

    The discriminant is equal to b^2 - 4 (a) (c). If the answer is a perfect square, then there are two real numbers. If not, then there are no real number root.

    The discriminant for this equation is

    (-6) ^2 - 4 (3) (1) = 24

    Since 24 is not a perfect square, there are no real number roots.
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