A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min how far does the car travel while it is accelerating

The acceleration is given by:

a = (v2-v1) / t

where

a=accelaration

v2=second velocity

v1=first velocity

thus the acceleration will be:

v1=6.5 m/s

v2=24 m/s

t=3.5min=210 sec

thus

a = (24-6.5) / 210

a=0.09286 m/s²

Answer: 0.09286 m/s²