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12 November, 01:08

A ball is thrown into the air with an initial upward velocity of 46ft/s. Its height (h) in feet after t seconds is given by the function h=-16t^2+46t+6. After how many seconds will the ball hit the ground?

A. 3

B. 4

C. 5

D. 6

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Answers (1)
  1. 12 November, 02:37
    0
    The answer is A: 3 feet; this answer can be obtained by finding the zeros of the equation above.
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