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25 May, 23:17

How to solve log base 5 of x + log base 5 of (4x-1)

Answers (1)
  1. B
    26 May, 01:08
    0
    Log5 (x) + log5 (4x-1)

    As the bases are the same the number doesn't matter

    Log (a) + log (b) = log (ab)

    Log (4x^2-x)

    (x) (4x-1)

    x=0.25 or x=0

    Log (4*0.25^2-0.25) = log (0) = Infinity

    Same with 0. So no answer
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