A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be green and the second will be green as well?

Question

Mathematics

Chelsea Casey

27 January, 08:25

A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be green and the second will be green as well?

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Answers (1)

Know the Answer?

Kaeden Cohen · Answer 1

It's a 6:18 probability of picking a green one or 1:3

Then you take another without putting the first one back in and the probability of it being green again would then be 5:17

A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans.If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be green and the second will be green as well?

A jar contains 6 red jelly beans, 6 green jelly beans, and 6 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be green and the second will be green as well?