What is the root of the polynomial equation x (x-2) (x+3) = 18? Use a graphing calculator and a system of equations.

-3

0

2

X (x-2) (x+3) = 18

(x²-2x) (x+3) = 18

x² (x+3) - 2x (x+3) = 18

x³ + 3x² - 2x² - 6x - 18 = 0

x³ + x² - 6x - 18 = 0

x² (x+1) - 6 (x-3) = 0

(x²-6) (x+1) (x-3) = 0

(x-3) (x+2) (x+1) (x-3) = 0

factors are x = 3; x = - 2; x = - 1