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10 December, 12:10

Question 987989: The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm. Rounded to the nearest tenth, what is the greatest possible value of x?

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  1. 10 December, 14:12
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    Given that the longest side is 20 cm, 3x < 20 and x <20/3

    Other inequality that has to be checked is that the sum of two any sides has to be greater than the other.

    Then 3x + x > 20

    4x > 20

    x > 5.

    So the value of x is in the range (5, 20/3)
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