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31 August, 07:21

How do you write the quadratic function f (x) = 3x2 - 6x + 9 in vertex form

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  1. 31 August, 10:38
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    F (x) = 3x^2 - 6x + 9 = 3 (x^2 - 2x + 3) = 3 (x^2 - 2x + 1 + 2) = 3 (x - 1) ^2 + 3 (2) = 3 (x - 1) ^2 + 6.

    Therefore, f (x) = 3x^2 - 6x + 9 in vertex form is f (x) = 3 (x - 1) ^2 + 6
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