What are the zeros of the function

f (x) = x^2-5x-24

8 and - 3

Start by factoring the equation:

(x + 3) (x - 8)

Then set each equal to zero and solve for each one.

We need to put this in factored form. I can explain factored form if you want, but for now I’ll just show you the result.

(X-8) (x+3)

We can check if this is the right equation.

X^2 + 3x-8x-24

So, we have the factored form and it will be very easy to find the zeros.

(X-8) (x+3)

We need for that to equal zero. Whenever you multiply anything by y zero, you’ll receive zero.

X=8, x=-3

They will satisfy the equation and will get you zero. Let’s check.

8^2-5 (8) - 24

64-40-24

24-24

0

So 8 works.

-3^2-5 (-3) - 24

9+15-24

24-24

0

So, the zeros are 8 and - 3.