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2 April, 06:11

If sinxcos (pi/7) - sin (pi/7) cosx=-sqrt2/2 then x can equal?

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Answers (2)
  1. 2 April, 08:53
    0
    3pi/4 and 7pi/4 are correct
  2. 2 April, 09:00
    0
    I'm going for a range of 0 < x <2 π

    This is R sin (x-a), although R is 1.

    a = π/7, so

    => sin (x - (π/7)) = - 1 / (sqrt (2))

    => x = 53 π/28, 39 π/28
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