The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 77 ft2. find the dimensions of the rectangle.

Hello:

let : y the length and : x the width

y = 2x + 3 ... (1)

xy = 77 ... (2)

by (1) subsct : y i n (2)

x (2x+3) = 77

2x²+3x - 77 = 0

the descrimnent : b²-4ac ... a = 2 b = 3 c = - 77

3²-4 (2) (-77) = 625 = 25²

x1 = (-3-25) / 4 negatif refused

x2 = (-3+25) / 4 = 22/4 = 11/2

x = 5.5

y = 2 (5.5) + 3 = 14