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8 March, 03:04

Which is the polar form of the parametric equations x=4 cos theta and y=4 sin theta?

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  1. 8 March, 04:17
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    To solve this problem you must apply the proccedure shown below:

    1. You have the following parametric equations given in the problem above:

    x=4cosθ

    y=4sinθ

    2. Therefore, you have:

    x=rcos θ

    y=rsin θ

    x=4cos θ

    rcosθ=4cos θ

    3. Solve for r:

    r=4cos θ/cos θ

    r=4

    Therefore, the answer is: r=4 and assuming that θ goes from 0 to 2 π.
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