What is the value of f (5) in the function.

f (x) = 2 (2) ^x-1

f (x) = 2 (2) ^x-1

The way you wrote, I really don't know it's f (x) = 2 (2) ^x - 1 or f (x) = 2 (2) ^ (x-1) ?

so i'm going to solve both

f (x) = 2 (2) ^x - 1

f (5) = 2 (2) ^5 - 1

f (5) = 2 (32) - 1

f (5) = 64 - 1

f (5) = 63

f (x) = 2 (2) ^ (x-1)

f (5) = 2 (2) ^ (5-1)

f (5) = 2 (2^4)

f (5) = 2 (16)

f (5) = 32

F (x) = 2 (2) ^x-1 f (5) = 32