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Mathematics
Duncan Cohen
2 June, 07:33
If x^2+2xy+y^2=8 find 3 (x+y) ^2
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Eleanor Valencia
2 June, 11:01
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3 (x + y) ² = 8
3 (x + y) (x + y) = 8
3 (x² + xy + xy + y²) = 8
3 (x² + 2xy + y²) = 8
3 (x²) + 3 (2xy) + 3 (y²) = 8
3x² + 6xy + 3y² = 8
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