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5 December, 22:33

What equation is graphed in this figure?

y-3=13 (x+1) y-3=13 (x+1)

y-5=3 (x-1) y-5=3 (x-1)

y-4=-13 (x+2) y-4=-13 (x+2)

y+2=-3 (x-1)

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  1. 6 December, 02:09
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    x^2+y^2=9 (an equation of a circle with a radius of 3) sin (x) + cos (y) = 0.52x-3y=1cos (x^2) = y (x-3) (x+3) = y^2 y=x^2
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