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29 May, 22:51

What is the logarithmic form of the equation e2x ≈ 1732?

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  1. 29 May, 23:49
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    E2x ≈ 1732, ln e2x ≈ ln 1732 and 2xlne = ln 1732, but lne=1, finally x = (1/2) ln1732
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