A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.34, what is the approximate stopping distance of the car?
a. 21 feet
b. 21 miles
c. 239 feet
d. 239 miles
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Home » Mathematics » A car's stopping distance in feet is modeled by the equation d (v) = 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. If the initial velocity of the car is 47 mph and f = 0.