Solve and graph the absolute value inequality: |2x + 1| ≤ 5.

A. number line with closed dots on negative 3 and 2 with shading going in the opposite directions.

B. number line with closed dots on negative 3 and 2 with shading in between.

C. number line with open dots on negative 3 and 2 with shading in between.

D. number line with closed dots on negative 2 and 2 with shading in between.

Question

Mathematics

Cannon Stein

31 August, 04:49

Solve and graph the absolute value inequality: |2x + 1| ≤ 5.

A. number line with closed dots on negative 3 and 2 with shading going in the opposite directions.

B. number line with closed dots on negative 3 and 2 with shading in between.

C. number line with open dots on negative 3 and 2 with shading in between.

D. number line with closed dots on negative 2 and 2 with shading in between.

+1

Answers (1)

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Nigel Williams · Answer 1

|2x + 1| < = 5

-5 < = 2x + 1 < = 5 ... subtract 1

-5 - 1 < = 2x + 1 - 1 < = 5 - 1

-6 < = 2x < = 4 ... divide by 2

-6/2 < = (2/2) x < = 4/2

-3 < = x < = 2

B. a number line with closed dots (because of the = sign) on - 3 and 2 with shading in between