If the sum of the first 60 positive integers is s, what is the sum of the first 120 integers in terms of s? a. 2s 3600 b. s^2 3600 c. s^2 - 3600 d. s 3600

For the first 60 positive integers, a = 1, n = 60, l = 60.

Sn = n/2 (a + l)

s = 60/2 (1 + 60) = 30 (61)

For the next 60 positive integer, a = 61, n = 60, l = 120

Sum = 60/2 (61 + 120) = 30 (61 + 120) = 30 (61) + 30 (120) = s + 3600

Sum of first 120 positive integers = s + s + 3600 = 2s + 3600