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2 July, 04:22

Find (gOf) (x)

f (x) = x^2 - (1/2x) + 4

g (x) = 8x-2

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Answers (2)
  1. 2 July, 04:38
    0
    F (x) = x^2 - (1/2) x+4

    g (x) = 8x-2

    (g o f) (x) = ?

    (g o f) (x) = g (f (x)) = g (x^2 - (1/2) x+4)

    x=x^2 - (1/2) x+4→g (x^2 - (1/2) x+4) = 8[x^2 - (1/2) x+4]-2

    g (x^2 - (1/2) x+4) = 8x^2-4x+32-2

    g (x^2 - (1/2) x+4) = 8x^2-4x+30

    Answer: (g o f) (x) = 8x^2-4x+30
  2. 2 July, 07:35
    0
    For this case, the first thing we must do is the composition of functions.

    We have:

    f (x) = x ^ 2 - (1 / 2x) + 4

    g (x) = 8x-2

    (gOf) (x) = 8 (x ^ 2 - (1 / 2x) + 4) - 2

    We rewrite: now the function:

    (gOf) (x) = 8x ^ 2 - (8/2) x + 32-2

    (gOf) (x) = 8x ^ 2-4x + 30

    Answer:

    The final result is:

    (gOf) (x) = 8x ^ 2-4x + 30
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