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25 August, 16:14

Suppose a researcher is interested in understanding the variation in the price of store brand milk. a random sample of 36 grocery stores is selected from a population and the mean price of store brand milk is calculated. the sample mean is $3.13 with a standard deviation of $0.23. construct a 99% confidence interval to estimate the population mean.

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  1. 25 August, 20:08
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    The confidence interval extremities are given by the formula:

    m + / - (z · σ / √n)

    In your problem:

    m = 3.13

    σ = 0.23

    n = 36

    The z-score for a 99% confidence interval is 2.576

    Therefore:

    m - (z · σ / √n) = 3.13 - (2.576 · 0.23 / √36) = 3.031

    m + (z · σ / √n) = 3.13 + (2.576 · 0.23 / √36) = 3.229

    Therefore, the confidence interval is (3.031, 3.229).
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