A sequence is defined by the recursive function f (n + 1) = - 10f (n). if f (1) = 1 what is f (3)

A) 3

B) - 30

C) 100

D) - 1,000

F (1+1) = - 10 (f (1)) where f (1) = 1

f (2) = - 10 (1)

f (2) = - 10

we are solving for f (3) so set f (n+1) equal to f (3)

f (n+1) = f (3)

n=2

we know what f (2) is so we do that so

f (2+1) = - 10 (f (2))

f (2) = - 10

f (3) = - 10 (-10)

f (3) = 100 (since negative times negative=positive

f (3) = 100

the answer is C, 100