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Yesterday, 22:04

Find the 39th term of the arithmetic sequence that starts with 4 and has a common difference of 6.

A. 232

B. 226

C. 238

D. None of these

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Answers (1)
  1. Today, 00:10
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    Any arithmetic sequence can be expressed as:

    a (n) = a+d (n-1), a=initial term, d=common difference, n=term number.

    We are told that a=4 and d=6 so we have:

    a (n) = 4+6 (n-1), so the 39th term is:

    a (39) = 4+6 (38)

    a (39) = 4+228

    a (39) = 232
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