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28 December, 10:08

What is the solution to the equation fraction 1 over 3 (n - fraction 1 over 3) = fraction 1 over 6n? n = 3 n = 2 n = fraction 5 over 6 n = fraction 2 over 3

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  1. 28 December, 11:58
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    1/3 (n - 1/3) = 1/6n

    1/3n - 1/9 = 1/6n

    -1/9 = 1/6n - 1/3n

    -1/9 = 1/6n - 2/6n

    -1/9 = - 1/6n

    -1/9 * - 6 = n

    6/9 = n

    2/3 = n
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