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5 November, 11:54

Find all solutions in the interval [0, 2π) sin2x + sin x = 0

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  1. 5 November, 12:41
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    Sin 2 x + sin x = 0

    (sin 2 x = 2 sin x cos x)

    2 sin x cos x + sin x = 0

    sin x (2 cos x + 1) = 0

    sin x = 0

    x 1 = 0

    x 2 = π

    or: 2 cos x + 1 = 0

    2 cos x = - 1

    cos x = - 1/2

    x 3 = 2π/3

    x 4 = 4π/3
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