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27 May, 17:12

Sandy releases a javelin 1.6 m above the ground with an initial vertical velocity of 25 m/s. How long will it take the javelin to hit the ground?

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  1. 27 May, 18:39
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    Time taken for the javelin to hit the ground will be given by:

    A (t) = V' (t) = S'' (t)

    A (t) = - 9.8m/s

    ⇒V (t) = - 9.8t/1+C m/s

    Where C is the initial velocity:

    ⇒V (t) = - 9.8t+25

    ⇒S (t) = - 9.8t²/2+25t/1+C

    ⇒S (t) = - 4.9t²+25t+C

    but the C is the initial vertical displacement, hence:

    S (t) = - 4.9t²+25t+1.6m

    The time taken to hit the ground will therefore be:

    S (t) = 0

    -4.9t²+25t+1.6=0
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