In meters, the sides of a triangle measure 14,18 and 12. The length of the longest side of a similar triangle is 21 meters.

a. Find the ratio of similitude of the two triangles

b. Find the lengths of the other two sides of the larger triangle.

c. Find the perimeter of each triangle

d. Is the ratio of the perimeters equal to the ratio of the lengths of the sides of the triangles?

Question

Mathematics

Ashlynn Marquez

7 August, 10:18

In meters, the sides of a triangle measure 14,18 and 12. The length of the longest side of a similar triangle is 21 meters.

a. Find the ratio of similitude of the two triangles

b. Find the lengths of the other two sides of the larger triangle.

c. Find the perimeter of each triangle

d. Is the ratio of the perimeters equal to the ratio of the lengths of the sides of the triangles?

+1

Answers (1)

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Hadley · Answer 1

Well, the ratio is 21/18 or 7/6 (you could take them the other way too)

The lengths you'd find using the same logic. Corresponding to 12 there is 14, while for 14 there is somewhere around 16.33. The perimeter of the smaller is 14+18+12=44, while for the larger it is around 51.33. The ratio of the perimeter is the same as the ratio of lengths.