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8 January, 15:07

A rock is thrown upwards from the top of a building 200 feet high with an initial velocity of 96 feet per second

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  1. 8 January, 16:31
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    T=3-√ 43/2=-1.63 and 3+√ 43/2=7.63

    and since time can't be negative, it hits the ground at 7.63 seconds.

    and then for 3 there are two steps. Use t = - b 2a to find the time of max height. Then plug that time into the h (t) equation

    the same values you used in the quadratic equation a = - 16, b = 96, c = 200

    t = - 96 2 (-16)

    344 is the answer.
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