Compute the value of the discriminant and give the number of real solutions of the quadratic equation. - 2x^2+8x-1=0

Question

Mathematics

Brett Nicholson

4 February, 07:19

Compute the value of the discriminant and give the number of real solutions of the quadratic equation. - 2x^2+8x-1=0

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Dario · Answer 1

Divide given eq. by - 2, we get, x^2-4x+0.5=0. Here a=1, b=-4 and c=0.5. As disccriminant is given by sqrt (b^2-4*a*c). so sqrt ((-4) ^2-4*1*0.5) = 3.7417.

Real roots are x1,2=-b+-discriminant

x1=-4+3.7417=-0.2583 and x2=-4-3.7417=-7.7417