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16 August, 16:14

The axis of symmetry for the function f (x) = - 2x2 + 4x + 1 is the line x = 1. Where is the vertex of the function located? (0, 1) (1, 3) (1, 7) (2, 1) ?

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  1. 16 August, 17:48
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    Hello:

    -2x²+4x+1 = - 2 (x-1) ²+b

    find : b

    -2x²+4x+1 = - 2 (x²-2x+1) + b

    -2x²+4x+1 = - 2x² + 4x - 2+b

    -2+b = 1

    b = 3

    -2x²+4x+1 = - 2 (x-1) ²+3

    the vertex of the function located is : (1, 3)
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