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6 August, 18:13

Susan is buying three different colors of tiles for her kitchen floor. She is buying 25 more red tiles than beige tiles, and three times as many navy-blue tiles as beige tiles. If Susan buys 435 tiles altogether, how many tiles of each color does she buy?

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  1. 6 August, 19:59
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    Let us assume that the number of beige tiles bought by Susan = B

    Number of red tiles bought by Susan = R

    Number of navy-blue tiles bought by Susan = N

    Number of tiles bought altogether = 435

    Now from the given question we know:

    Number of red tiles bought is 25 more than the number of beige tiles.

    So

    R = 25 + B

    Number of navy blue tiles bought is 3 times that of the number of beige tile bought

    So

    N = 3B

    We already know that the total number of tiles bought is 435

    Hence

    B + R + N = 435

    B + (25 + B) + 3B = 435

    5B + 25 = 435

    5B = 435 - 25

    5B = 410

    B = 82

    R = 25 + B

    = 25 + 82

    = 107

    N = 3B

    = 3 * 82

    = 246

    So the number of Beige tiles bought by Susan = 82

    The number of red tiles bought by Susan = 107

    The number of navy-blue tiles bought by Susan = 246
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