The sixth term is 22 and the difference is 6 what would be your 50term

The general formula for an arithmetic sequence is:

a (n) = a + d (n - 1)

a : first term

d : common difference (6)

n : number of the term

In your example, you are told the 6th term is 22.

a (6) = a + 6 (6 - 1) = 22

a + 30 = 22

a = 22 - 30

a = - 8

So now you have the general formula:

a (n) = - 8 + 6 (n - 1)

If you like you can simplify it:

a (n) = - 8 + 6n - 6

a (n) = 6n - 14

Then you can plug in n = 50:

a (50) = 6 (50) - 14

= 300 - 14

= 286

Assuming y ou mean aritmetic sequence since you said 'difference' as in 'common difference'

an=a1+d (n-1)

given

6th term is 22

and difference is 6

that means

a6=a1+6 (6-1) = 22

22=a1+6 (5)

22=a1+30

minus 30 both sides

-8=a1

so we now have

an=-8+6 (n-1)

find 50th term

a50=-8+6 (50-1)

a50=-8+6 (49)

a50=-8+294

a50=286

50th term is 286