Ask Question
19 December, 06:40

5y/y^2+3y-4 - y-1/y^2-1

+4
Answers (2)
  1. 19 December, 07:31
    0
    5y - y - 1 = 5y (y² - 1) - (y - 1) (y² + 3y - 4) =

    y² + 3y - 4 y² - 1 (y² + 3 - 4) (y² - 1) (y² + 3 - 4) (y² - 1)

    5y³ - 5 - y³ + 3y² - 8y + 4 = 5y³ - y³ + 3y² - 8y - 5 - 4 = 4y³ + 3y² - 8y - 9

    y^4 + 6y² + 1 y^4 + 6y² + 1 y^4 + 6y² + 1 y^4 + 6y² + 1
  2. 19 December, 09:27
    0
    I think that the answer will be

    5y/y^2+3y-4 - y-1/y^2-1

    5/y+2y-5-1/y^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “5y/y^2+3y-4 - y-1/y^2-1 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers