Ask Question
15 December, 02:02

In a sample of 1000 adults, 150 said they are very confident in the nutritional information on restaurant menus. for us adults are selected at random without replacement. find the probability that all four us adults are very confident in the nutritional information on menus

+4
Answers (1)
  1. 15 December, 04:37
    0
    There are 150 confident adults out of 1000.

    Selecting four at random withOUT replacement

    Probability that all four are confident

    = (150/100*149/999*148/997*147/996)

    =150!/146! / (1000!/996!)

    = 7301/14925090

    = 0.00048918

    (check: answer < (150/1000) ^4=0.00050625, ok)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In a sample of 1000 adults, 150 said they are very confident in the nutritional information on restaurant menus. for us adults are selected ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers