Solve the IVP:

dx/dt=1/x

dy/dt=x^2+2y

Y0 = (1,2)

Use the nullclines technique to sketch the solution on the phase plane.

Question

Jakobe Church

13 August, 10:08

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River Cruz · Answer 1

We are lacking one initial condition for x. There is therefore no unique solution to the problem by Cauchy's theorem.

Solve the IVP:dx/dt=1/xdy/dt=x^2+2yY0 = (1,2)Use the nullclines technique to sketch the solution on the phase plane.