Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.

y = - 2x + 4

6x + 3y =

A: - 12

B: - 4

C: 0

D: 4

E: 12

Question

Mathematics

Gay

26 November, 21:08

Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.

y = - 2x + 4

6x + 3y =

A: - 12

B: - 4

C: 0

D: 4

E: 12

+4

Answers (1)

Know the Answer?

Sandra Johnson · Answer 1

6x + 3y = ?

3y = - 6x + ?

y = - 6/3x + ?/3

y = - 2x + ?/3

y = - 2x + 4

no solutions means they are going to be parallel lines. That means they will have the same slope (-2) and different y int. So that blank space can be anything but 4 or 12 ... the reason 12 is also included is because 12/3 = 4.

answers are : - 12, - 4, 0

Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.y = - 2x + 46x + 3y =A: - 12B: - 4C: 0D: 4E: 12

Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.

y = - 2x + 4

6x + 3y =

A: - 12

B: - 4

C: 0

D: 4

E: 12