Find two positive numbers so that twice their sum equals their product and one number is 3 times the other number. Enter the smaller number first.

X and y

2 (x+y) = xy

x is 3 times y

x=3y

easy, sub 3y for x

2 (3y+y) = (3y) y

2 (4y) = 3y²

8y=3y²

divide both sides by y

8=3y

divdie both sides by 3

8/3=y

sub back

x=3y

x=3 (8/3)

x=8

the smaller number is 8/3

larger is 8