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MathematicsMathematics
18 January, 01:21

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.

length = 1 yd, width = 20 yd

length = 2 yd, width = 10 yd

length = 10 yd, width = 2 yd

length = 20 yd, width = 1 y

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Answers (1)
  1. 18 January, 05:00
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    The answer is length = 10 yd, width = 2 yd

    proof

    The length of the playground is 5 times longer than its width, it means

    l=5w, but 10 = 2x5 so we can write l = 5w,

    and Area = 20 = l x w = (5x2) x 2 = 20
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