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18 May, 02:57

Given the function f (x) = log5 (x + 1), find the value of f-1 (2).

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  1. 18 May, 04:35
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    F (x) = log (5) (x + 1)

    y = log (5) (x + 1)

    x + 1 = 5^y

    x = 5^y - 1

    f (-1) (x) = 5^x - 1

    f (-1) (2) = 5^2 - 1 = 25 - 1 = 24
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