Ask Question
23 February, 06:51

Calculate work of a man holding a barbell at chest hight 2 m for 15 seconds?

+1
Answers (1)
  1. 23 February, 07:11
    0
    Answer: 0J

    The equation for work is W=Fdcos (x), where w=work, f=force, d=displacement, and x=angle the force makes with the displacement vector.

    Since the man is holding a barbell and the object, the barbell, isn't being displaced, d=0, making the work done equal to zero.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate work of a man holding a barbell at chest hight 2 m for 15 seconds? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers