In the lab, Manuel has two solutions that contain alcohol and is mixing them with each other. Solution A is 50% alcohol and Solution B is 10% alcohol. He uses 1200 milliliters of solution A. How many milliliters of Solution B does he use if the resulting mixture is a 40% alcohol solution?

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Rashad Ford

11 December, 10:44

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Monique Becker · Answer 1

Suppose he uses x mls of solution B.

0.5*1200 + 0.1x=0.4 (1200+x)

600+0.1x=480+0.4x

0.3x=120

x=400