Find the 12th partial sum of the summation of negative 2i minus 10, from i equals 1 to infinity.

25

40

-276

72

The answer to your question is C.-276

The given equation is:

x = - 2i - 10

Calculating for values of i = 1 to 12

x (1) = - 2 - 10 = - 12

x (2) = - 4 - 10 = - 14

x (3) = - 6 - 10 = - 16

x (4) = - 8 - 10 = - 18

x (5) = - 10 - 10 = - 20

x (6) = - 12 - 10 = - 22

x (7) = - 14 - 10 = - 24

x (8) = - 16 - 10 = - 26

x (9) = - 18 - 10 = - 28

x (10) = - 20 - 10 = - 30

x (11) = - 22 - 10 = - 32

x (12) = - 24 - 10 = - 34

Getting the sum of all:

12th partial sum = - 276