Given the number 456789abh, list out its byte value in little-endian order

The given 32-bit value is 456789ab in hexadecimal notation.

Each byte uses two hex digits.

The 4 bytes contained in the number are

45 67 89 ab.

Little-endian order stores the least significant bytes first in the smallest memory address.

Therefore the storage in little-endian order is

ab

89

67

45

Answer:

The byte values are ab, 89, 67, 45