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2 October, 13:14

In a random sample of 60 computers, the mean repair cost was $150. Assume the population standard deviation is $36. Construct a 90% confidence interval for the population mean.

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  1. 2 October, 15:33
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    Given that:

    x_bar=150, σ=36, n=60

    The 90% confidence interval will be found as follows:

    +/-1.65 (36/sqrt (60))

    =+/-1.65 (4.64758)

    =+/-7.6685

    Thus our answer will be:

    150+/-7.6685

    =157.6685 or 142.3315
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