How do i get the answer for this limit limit x to 0 (4^2x-1)

without using direct substitution my work so far is limit x to 0 = (4^2x-1) = (4^2x/4^-1) is it correct?

Question

Reginald Ward

2 October, 00:23

+2

Answers (1)

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Neil Petty · Answer 1

Lim 4^ (2x-1)

x-->0

= 4^ (2 (0) - 1)

=4^ (-1)

=1/4

How do i get the answer for this limit limit x to 0 (4^2x-1)without using direct substitution my work so far is limit x to 0 = (4^2x-1) = (4^2x/4^-1) is it correct?