How do i get the answer for this limit limit x to 0 (4^2x-1)

without using direct substitution my work so far is limit x to 0 = (4^2x-1) = (4^2x/4^-1) is it correct?

F (x) = 4x2-8x-60 f (x) = 4 (x2-2x-15) f (x) = 4 (x-5) (x+3) whts the true statement of f (x) A The zeros of f (x) are - 5 and 3. B The vertex of the graph of f (x) is (-5, 3). C The vertex of the graph of f (x) is (5, - 3).

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