What is the Vertex y=2x^2+6

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Mathematics

Belen Stewart

30 August, 16:51

What is the Vertex y=2x^2+6

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Aaron Ingram · Answer 1

Compare this function to y=ax^2 + bx + c. You can readily see that a=2, b=0 and c=6.

The x-coord. of the vertex is at x = - b / (2a). Subbing the given values for a and b, we get

x = - (0) / (2 (2) = 0. At x = 0, y = 6, so the vertex of this parabola is (0,6). It opens upward.