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5 November, 04:19

If u (x) = - 2x^2+3 and v (x) = 1/x, what is the range of (uov) (x) ?

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  1. 5 November, 06:40
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    U (x) = - 2x²+3

    v (x) = 1/x →→ range of (uоv) (x, BUT range (uov) (x = u (v (x)), then:

    u (v (x)) = - 2 (1/x²) + 3 →→u (v (x)) = - 2/x² + 3

    The range of - 2/x² + 3 = {x∈R/x≠0}
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