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1 July, 06:58

f (x) = 3/2 x+b

in the function above, b is a constant. if f (6) = 7, what is the value of f (-2) ?

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  1. 1 July, 08:44
    0
    F (x) = 3/2 x+b

    1) we have to calculate b

    f (6) = 7 ⇒ 3/2 (6) + b=7

    9+b=7

    b=7-9

    b=-2

    Then: f (x) = 3/2 x - 2

    2) Now, we calculate f (-2):

    f (-2) = 3/2 (-2) - 2=-3-2=-5

    Answer: f (-2) = - 5
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